DBE Kn(O)/Kn(I)

[landmeister]

I'm not sure this is the correct forum for this question, but here I go. I read on Appendix IV that Feudal (at least) German DBE can be Kn(O)/Kn(I). Does anyone know if this reading is correct? Will this be a new sort of Kn DBE?

Thank you

[Barritus]

We won't know for sure until Book 4 comes out. But I see no need to be surprised. After all, the Kn DBEs in the Nikephorian Byzantine list are Kn (X) in the front rank and Kn (I) in the rear.

[landmeister]

I see. Thank you.